# Appendix¶

## KF Basics - Part I¶

### Introduction¶

#### What is the need to describe belief in terms of PDF’s?¶

This is because robot environments are stochastic. A robot environment may have cows with Tesla by side. That is a robot and it’s environment cannot be deterministically modelled(e.g as a function of something like time t). In the real world sensors are also error prone, and hence there’ll be a set of values with a mean and variance that it can take. Hence, we always have to model around some mean and variances associated.

#### What is Expectation of a Random Variables?¶

Expectation is nothing but an average of the probabilites

$\mathbb E[X] = \sum_{i=1}^n p_ix_i$

In the continous form,

$\mathbb E[X] = \int_{-\infty}^\infty x\, f(x) \,dx$
import numpy as np
import random
x=[3,1,2]
p=[0.1,0.3,0.4]
E_x=np.sum(np.multiply(x,p))
print(E_x)

1.4000000000000001


#### What is the advantage of representing the belief as a unimodal as opposed to multimodal?¶

Obviously, it makes sense because we can’t multiple probabilities to a car moving for two locations. This would be too confusing and the information will not be useful.

### Variance, Covariance and Correlation¶

#### Variance¶

Variance is the spread of the data. The mean does’nt tell much about the data. Therefore the variance tells us about the story about the data meaning the spread of the data.

$\mathit{VAR}(X) = \frac{1}{n}\sum_{i=1}^n (x_i - \mu)^2$
x=np.random.randn(10)
np.var(x)

1.0224618077401504


#### Covariance¶

This is for a multivariate distribution. For example, a robot in 2-D space can take values in both x and y. To describe them, a normal distribution with mean in both x and y is needed.

For a multivariate distribution, mean $$\mu$$ can be represented as a matrix,

$\begin{split}\mu = \begin{bmatrix}\mu_1\\\mu_2\\ \vdots \\\mu_n\end{bmatrix}\end{split}$

Similarly, variance can also be represented.

But an important concept is that in the same way as every variable or dimension has a variation in its values, it is also possible that there will be values on how they together vary. This is also a measure of how two datasets are related to each other or correlation.

For example, as height increases weight also generally increases. These variables are correlated. They are positively correlated because as one variable gets larger so does the other.

We use a covariance matrix to denote covariances of a multivariate normal distribution:

$\begin{split}\Sigma = \begin{bmatrix} \sigma_1^2 & \sigma_{12} & \cdots & \sigma_{1n} \\ \sigma_{21} &\sigma_2^2 & \cdots & \sigma_{2n} \\ \vdots & \vdots & \ddots & \vdots \\ \sigma_{n1} & \sigma_{n2} & \cdots & \sigma_n^2 \end{bmatrix}\end{split}$

Diagonal - Variance of each variable associated.

Off-Diagonal - covariance between ith and jth variables.

\begin{split}\begin{aligned}VAR(X) = \sigma_x^2 &= \frac{1}{n}\sum_{i=1}^n(X - \mu)^2\\ COV(X, Y) = \sigma_{xy} &= \frac{1}{n}\sum_{i=1}^n[(X-\mu_x)(Y-\mu_y)\big]\end{aligned}\end{split}
x=np.random.random((3,3))
np.cov(x)

array([[0.08868895, 0.05064471, 0.08855629],
[0.05064471, 0.06219243, 0.11555291],
[0.08855629, 0.11555291, 0.21534324]])


Covariance taking the data as sample with $$\frac{1}{N-1}$$

x_cor=np.random.rand(1,10)
y_cor=np.random.rand(1,10)
np.cov(x_cor,y_cor)

array([[ 0.1571437 , -0.00766623],
[-0.00766623,  0.13957621]])


Covariance taking the data as population with $$\frac{1}{N}$$

np.cov(x_cor,y_cor,bias=1)

array([[ 0.14142933, -0.0068996 ],
[-0.0068996 ,  0.12561859]])


### Gaussians¶

#### Central Limit Theorem¶

According to this theorem, the average of n samples of random and independent variables tends to follow a normal distribution as we increase the sample size.(Generally, for n>=30)

import matplotlib.pyplot as plt
import random
a=np.zeros((100,))
for i in range(100):
x=[random.uniform(1,10) for _ in range(1000)]
a[i]=np.sum(x,axis=0)/1000
plt.hist(a)

(array([ 1.,  4.,  9., 12., 12., 20., 16., 16.,  4.,  6.]),
array([5.30943011, 5.34638597, 5.38334183, 5.42029769, 5.45725355,
5.49420941, 5.53116527, 5.56812114, 5.605077  , 5.64203286,
5.67898872]),
<a list of 10 Patch objects>)


#### Gaussian Distribution¶

A Gaussian is a continuous probability distribution that is completely described with two parameters, the mean ($$\mu$$) and the variance ($$\sigma^2$$). It is defined as:

\begin{align}\begin{aligned} f(x, \mu, \sigma) = \frac{1}{\sigma\sqrt{2\pi}} \exp\big [{-\frac{(x-\mu)^2}{2\sigma^2} }\big ]\\Range is\end{aligned}\end{align}
$[-\inf,\inf]$

This is just a function of mean($$\mu$$) and standard deviation ($$\sigma$$) and what gives the normal distribution the charecteristic bell curve.

import matplotlib.mlab as mlab
import math
import scipy.stats

mu = 0
variance = 5
sigma = math.sqrt(variance)
x = np.linspace(mu - 5*sigma, mu + 5*sigma, 100)
plt.plot(x,scipy.stats.norm.pdf(x, mu, sigma))
plt.show()


#### Why do we need Gaussian distributions?¶

Since it becomes really difficult in the real world to deal with multimodal distribution as we cannot put the belief in two seperate location of the robots. This becomes really confusing and in practice impossible to comprehend. Gaussian probability distribution allows us to drive the robots using only one mode with peak at the mean with some variance.

### Gaussian Properties¶

Multiplication

For the measurement update in a Bayes Filter, the algorithm tells us to multiply the Prior P(X_t) and measurement P(Z_t|X_t) to calculate the posterior:

$P(X \mid Z) = \frac{P(Z \mid X)P(X)}{P(Z)}$

Here for the numerator, $$P(Z \mid X),P(X)$$ both are gaussian.

$$N(\bar\mu, \bar\sigma^1)$$ and $$N(\bar\mu, \bar\sigma^2)$$ are their mean and variances.

New mean is

\begin{align}\begin{aligned}\mu_\mathtt{new} = \frac{\sigma_z^2\bar\mu + \bar\sigma^2z}{\bar\sigma^2+\sigma_z^2}\\New variance is\end{aligned}\end{align}
$\sigma_\mathtt{new} = \frac{\sigma_z^2\bar\sigma^2}{\bar\sigma^2+\sigma_z^2}$
import matplotlib.mlab as mlab
import math
mu1 = 0
variance1 = 2
sigma = math.sqrt(variance1)
x1 = np.linspace(mu1 - 3*sigma, mu1 + 3*sigma, 100)
plt.plot(x1,scipy.stats.norm.pdf(x1, mu1, sigma),label='prior')

mu2 = 10
variance2 = 2
sigma = math.sqrt(variance2)
x2 = np.linspace(mu2 - 3*sigma, mu2 + 3*sigma, 100)
plt.plot(x2,scipy.stats.norm.pdf(x2, mu2, sigma),"g-",label='measurement')

mu_new=(mu1*variance2+mu2*variance1)/(variance1+variance2)
print("New mean is at: ",mu_new)
var_new=(variance1*variance2)/(variance1+variance2)
print("New variance is: ",var_new)
sigma = math.sqrt(var_new)
x3 = np.linspace(mu_new - 3*sigma, mu_new + 3*sigma, 100)
plt.plot(x3,scipy.stats.norm.pdf(x3, mu_new, var_new),label="posterior")
plt.legend(loc='upper left')
plt.xlim(-10,20)
plt.show()

New mean is at:  5.0
New variance is:  1.0


The motion step involves a case of adding up probability (Since it has to abide the Law of Total Probability). This means their beliefs are to be added and hence two gaussians. They are simply arithmetic additions of the two.

$\begin{split}\begin{gathered}\mu_x = \mu_p + \mu_z \\ \sigma_x^2 = \sigma_z^2+\sigma_p^2\, \square\end{gathered}\end{split}$
import matplotlib.mlab as mlab
import math
mu1 = 5
variance1 = 1
sigma = math.sqrt(variance1)
x1 = np.linspace(mu1 - 3*sigma, mu1 + 3*sigma, 100)
plt.plot(x1,scipy.stats.norm.pdf(x1, mu1, sigma),label='prior')

mu2 = 10
variance2 = 1
sigma = math.sqrt(variance2)
x2 = np.linspace(mu2 - 3*sigma, mu2 + 3*sigma, 100)
plt.plot(x2,scipy.stats.norm.pdf(x2, mu2, sigma),"g-",label='measurement')

mu_new=mu1+mu2
print("New mean is at: ",mu_new)
var_new=(variance1+variance2)
print("New variance is: ",var_new)
sigma = math.sqrt(var_new)
x3 = np.linspace(mu_new - 3*sigma, mu_new + 3*sigma, 100)
plt.plot(x3,scipy.stats.norm.pdf(x3, mu_new, var_new),label="posterior")
plt.legend(loc='upper left')
plt.xlim(-10,20)
plt.show()

New mean is at:  15
New variance is:  2

#Example from:
#https://scipython.com/blog/visualizing-the-bivariate-gaussian-distribution/
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import cm
from mpl_toolkits.mplot3d import Axes3D

# Our 2-dimensional distribution will be over variables X and Y
N = 60
X = np.linspace(-3, 3, N)
Y = np.linspace(-3, 4, N)
X, Y = np.meshgrid(X, Y)

# Mean vector and covariance matrix
mu = np.array([0., 1.])
Sigma = np.array([[ 1. , -0.5], [-0.5,  1.5]])

# Pack X and Y into a single 3-dimensional array
pos = np.empty(X.shape + (2,))
pos[:, :, 0] = X
pos[:, :, 1] = Y

def multivariate_gaussian(pos, mu, Sigma):
"""Return the multivariate Gaussian distribution on array pos.

pos is an array constructed by packing the meshed arrays of variables
x_1, x_2, x_3, ..., x_k into its _last_ dimension.

"""

n = mu.shape[0]
Sigma_det = np.linalg.det(Sigma)
Sigma_inv = np.linalg.inv(Sigma)
N = np.sqrt((2*np.pi)**n * Sigma_det)
# This einsum call calculates (x-mu)T.Sigma-1.(x-mu) in a vectorized
# way across all the input variables.
fac = np.einsum('...k,kl,...l->...', pos-mu, Sigma_inv, pos-mu)

return np.exp(-fac / 2) / N

# The distribution on the variables X, Y packed into pos.
Z = multivariate_gaussian(pos, mu, Sigma)

# Create a surface plot and projected filled contour plot under it.
fig = plt.figure()
ax = fig.gca(projection='3d')
ax.plot_surface(X, Y, Z, rstride=3, cstride=3, linewidth=1, antialiased=True,
cmap=cm.viridis)

cset = ax.contourf(X, Y, Z, zdir='z', offset=-0.15, cmap=cm.viridis)

# Adjust the limits, ticks and view angle
ax.set_zlim(-0.15,0.2)
ax.set_zticks(np.linspace(0,0.2,5))
ax.view_init(27, -21)

plt.show()


This is a 3D projection of the gaussians involved with the lower surface showing the 2D projection of the 3D projection above. The innermost ellipse represents the highest peak, that is the maximum probability for a given (X,Y) value.

** numpy einsum examples **

a = np.arange(25).reshape(5,5)
b = np.arange(5)
c = np.arange(6).reshape(2,3)
print(a)
print(b)
print(c)

[[ 0  1  2  3  4]
[ 5  6  7  8  9]
[10 11 12 13 14]
[15 16 17 18 19]
[20 21 22 23 24]]
[0 1 2 3 4]
[[0 1 2]
[3 4 5]]

#this is the diagonal sum, i repeated means the diagonal
np.einsum('ij', a)
#this takes the output ii which is the diagonal and outputs to a
np.einsum('ii->i',a)
#this takes in the array A represented by their axes 'ij' and  B by its only axes'j'
#and multiples them element wise
np.einsum('ij,j',a, b)

array([ 30,  80, 130, 180, 230])

A = np.arange(3).reshape(3,1)
B = np.array([[ 0,  1,  2,  3],
[ 4,  5,  6,  7],
[ 8,  9, 10, 11]])
C=np.multiply(A,B)
np.sum(C,axis=1)

array([ 0, 22, 76])

D = np.array([0,1,2])
E = np.array([[ 0,  1,  2,  3],
[ 4,  5,  6,  7],
[ 8,  9, 10, 11]])

np.einsum('i,ij->i',D,E)

array([ 0, 22, 76])

from scipy.stats import multivariate_normal
x, y = np.mgrid[-5:5:.1, -5:5:.1]
pos = np.empty(x.shape + (2,))
pos[:, :, 0] = x; pos[:, :, 1] = y
rv = multivariate_normal([0.5, -0.2], [[2.0, 0.9], [0.9, 0.5]])
plt.contourf(x, y, rv.pdf(pos))

<matplotlib.contour.QuadContourSet at 0x139196438>


### References:¶

1. Roger Labbe’s repo on Kalman Filters. (Majority of the examples in the notes are from this)
2. Probabilistic Robotics by Sebastian Thrun, Wolfram Burgard and Dieter Fox, MIT Press.
3. Scipy Documentation

## KF Basics - Part 2¶

### Probabilistic Generative Laws¶

#### 1st Law:¶

The belief representing the state $$x_{t}$$, is conditioned on all past states, measurements and controls. This can be shown mathematically by the conditional probability shown below:

$p(x_{t} | x_{0:t-1},z_{1:t-1},u_{1:t})$
1. $$z_{t}$$ represents the measurement
2. $$u_{t}$$ the motion command
3. $$x_{t}$$ the state (can be the position, velocity, etc) of the robot or its environment at time t.

‘If we know the state $$x_{t-1}$$ and $$u_{t}$$, then knowing the states $$x_{0:t-2}$$, $$z_{1:t-1}$$ becomes immaterial through the property of conditional independence’. The state $$x_{t-1}$$ introduces a conditional independence between $$x_{t}$$ and $$z_{1:t-1}$$, $$u_{1:t-1}$$

Therefore the law now holds as:

$p(x_{t} | x_{0:t-1},z_{1:t-1},u_{1:t})=p(x_{t} | x_{t-1},u_{t})$

#### 2nd Law:¶

If $$x_{t}$$ is complete, then:

$p(z_{t} | x-_{0:t},z_{1:t-1},u_{1:t})=p(z_{t} | x_{t})$

$$x_{t}$$ is complete means that the past states, controls or measurements carry no additional information to predict future.

$$x_{0:t-1}$$, $$z_{1:t-1}$$ and $$u_{1:t}$$ are conditionally independent of $$z_{t}$$ given $$x_{t}$$ of complete.

The filter works in two parts:

$$p(x_{t} | x_{t-1},u_{t})$$ -> State Transition Probability

$$p(z_{t} | x_{t})$$ -> Measurement Probability

### Conditional dependence and independence example:¶

$$\bullet$$Independent but conditionally dependent

Let’s say you flip two fair coins

C - Your first two flips were the same

A and B here are independent. However, A and B are conditionally dependent given C, since if you know C then your first coin flip will inform the other one.

$$\bullet$$Dependent but conditionally independent

A box contains two coins: a regular coin and one fake two-headed coin ((P(H)=1). I choose a coin at random and toss it twice. Define the following events.

A= First coin toss results in an H.

B= Second coin toss results in an H.

C= Coin 1 (regular) has been selected.

If we know A has occurred (i.e., the first coin toss has resulted in heads), we would guess that it is more likely that we have chosen Coin 2 than Coin 1. This in turn increases the conditional probability that B occurs. This suggests that A and B are not independent. On the other hand, given C (Coin 1 is selected), A and B are independent.

### Bayes Rule:¶

Posterior =

$\frac{Likelihood*Prior}{Marginal}$

Here,

Posterior = Probability of an event occurring based on certain evidence.

Likelihood = How probable is the evidence given the event.

Prior = Probability of the just the event occurring without having any evidence.

Marginal = Probability of the evidence given all the instances of events possible.

Example:

1% of women have breast cancer (and therefore 99% do not). 80% of mammograms detect breast cancer when it is there (and therefore 20% miss it). 9.6% of mammograms detect breast cancer when its not there (and therefore 90.4% correctly return a negative result).

We can turn the process above into an equation, which is Bayes Theorem. Here is the equation:

$$\displaystyle{\Pr(\mathrm{A}|\mathrm{X}) = \frac{\Pr(\mathrm{X}|\mathrm{A})\Pr(\mathrm{A})}{\Pr(\mathrm{X|A})\Pr(\mathrm{A})+ \Pr(\mathrm{X | not \ A})\Pr(\mathrm{not \ A})}}$$

$$\bullet$$Pr(A|X) = Chance of having cancer (A) given a positive test (X). This is what we want to know: How likely is it to have cancer with a positive result? In our case it was 7.8%.

$$\bullet$$Pr(X|A) = Chance of a positive test (X) given that you had cancer (A). This is the chance of a true positive, 80% in our case.

$$\bullet$$Pr(A) = Chance of having cancer (1%).

$$\bullet$$Pr(not A) = Chance of not having cancer (99%).

$$\bullet$$Pr(X|not A) = Chance of a positive test (X) given that you didn’t have cancer (~A). This is a false positive, 9.6% in our case.

### Bayes Filter Algorithm¶

The basic filter algorithm is:

for all $$x_{t}$$:

1. $$\overline{bel}(x_t) = \int p(x_t | u_t, x_{t-1}) bel(x_{t-1})dx$$
2. $$bel(x_t) = \eta p(z_t | x_t) \overline{bel}(x_t)$$

end.

$$\rightarrow$$The first step in filter is to calculate the prior for the next step that uses the bayes theorem. This is the Prediction step. The belief, $$\overline{bel}(x_t)$$, is before incorporating measurement($$z_{t}$$) at time t=t. This is the step where the motion occurs and information is lost because the means and covariances of the gaussians are added. The RHS of the equation incorporates the law of total probability for prior calculation.

$$\rightarrow$$ This is the Correction or update step that calculates the belief of the robot after taking into account the measurement($$z_{t}$$) at time t=t. This is where we incorporate the sensor information for the whereabouts of the robot. We gain information here as the gaussians get multiplied here. (Multiplication of gaussian values allows the resultant to lie in between these numbers and the resultant covariance is smaller.

### Bayes filter localization example:¶

from IPython.display import Image
Image(filename="bayes_filter.png",width=400)


Given - A robot with a sensor to detect doorways along a hallway. Also, the robot knows how the hallway looks like but doesn’t know where it is in the map.

1. Initially(first scenario), it doesn’t know where it is with respect to the map and hence the belief assigns equal probability to each location in the map.
2. The first sensor reading is incorporated and it shows the presence of a door. Now the robot knows how the map looks like but cannot localize yet as map has 3 doors present. Therefore it assigns equal probability to each door present.
3. The robot now moves forward. This is the prediction step and the motion causes the robot to lose some of the information and hence the variance of the gaussians increase (diagram 4.). The final belief is convolution of posterior from previous step and the current state after motion. Also, the means shift on the right due to the motion.
4. Again, incorporating the measurement, the sensor senses a door and this time too the possibility of door is equal for the three door. This is where the filter’s magic kicks in. For the final belief (diagram 5.), the posterior calculated after sensing is mixed or convolution of previous posterior and measurement. It improves the robot’s belief at location near to the second door. The variance decreases and peaks.
5. Finally after series of iterations of motion and correction, the robot is able to localize itself with respect to the environment.(diagram 6.)

Do note that the robot knows the map but doesn’t know where exactly it is on the map.

### Bayes and Kalman filter structure¶

The basic structure and the concept remains the same as bayes filter for Kalman. The only key difference is the mathematical representation of Kalman filter. The Kalman filter is nothing but a bayesian filter that uses Gaussians.

For a bayes filter to be a Kalman filter, each term of belief is now a gaussian, unlike histograms. The basic formulation for the bayes filter algorithm is:

\begin{split}\begin{aligned} \bar {\mathbf x} &= \mathbf x \ast f_{\mathbf x}(\bullet)\, \, &\text{Prediction} \\ \mathbf x &= \mathcal L \cdot \bar{\mathbf x}\, \, &\text{Correction} \end{aligned}\end{split}

$$\bar{\mathbf x}$$ is the prior

$$\mathcal L$$ is the likelihood of a measurement given the prior $$\bar{\mathbf x}$$

$$f_{\mathbf x}(\bullet)$$ is the process model or the gaussian term that helps predict the next state like velocity to track position or acceleration.

$$\ast$$ denotes convolution.

### Kalman Gain¶

$x = (\mathcal L \bar x)$

Where x is posterior and $$\mathcal L$$ and $$\bar x$$ are gaussians.

Therefore the mean of the posterior is given by:

$\mu=\frac{\bar\sigma^2\, \mu_z + \sigma_z^2 \, \bar\mu} {\bar\sigma^2 + \sigma_z^2}$
$\mu = \left( \frac{\bar\sigma^2}{\bar\sigma^2 + \sigma_z^2}\right) \mu_z + \left(\frac{\sigma_z^2}{\bar\sigma^2 + \sigma_z^2}\right)\bar\mu$

In this form it is easy to see that we are scaling the measurement and the prior by weights:

$\mu = W_1 \mu_z + W_2 \bar\mu$

The weights sum to one because the denominator is a normalization term. We introduce a new term, $$K=W_1$$, giving us:

\begin{split}\begin{aligned} \mu &= K \mu_z + (1-K) \bar\mu\\ &= \bar\mu + K(\mu_z - \bar\mu) \end{aligned}\end{split}

where

$K = \frac {\bar\sigma^2}{\bar\sigma^2 + \sigma_z^2}$

The variance in terms of the Kalman gain:

\begin{split}\begin{aligned} \sigma^2 &= \frac{\bar\sigma^2 \sigma_z^2 } {\bar\sigma^2 + \sigma_z^2} \\ &= K\sigma_z^2 \\ &= (1-K)\bar\sigma^2 \end{aligned}\end{split}

$$K$$ is the Kalman gain. It’s the crux of the Kalman filter. It is a scaling term that chooses a value partway between $$\mu_z$$ and $$\bar\mu$$.

### Kalman Filter - Univariate and Multivariate¶

Prediction

$$\begin{array}{|l|l|l|} \hline \text{Univariate} & \text{Univariate} & \text{Multivariate}\\ & \text{(Kalman form)} & \\ \hline \bar \mu = \mu + \mu_{f_x} & \bar x = x + dx & \bar{\mathbf x} = \mathbf{Fx} + \mathbf{Bu}\\ \bar\sigma^2 = \sigma_x^2 + \sigma_{f_x}^2 & \bar P = P + Q & \bar{\mathbf P} = \mathbf{FPF}^\mathsf T + \mathbf Q \\ \hline \end{array}$$

$$\mathbf x,\, \mathbf P$$ are the state mean and covariance. They correspond to $$x$$ and $$\sigma^2$$.

$$\mathbf F$$ is the state transition function. When multiplied by $$\bf x$$ it computes the prior.

$$\mathbf Q$$ is the process covariance. It corresponds to $$\sigma^2_{f_x}$$.

$$\mathbf B$$ and $$\mathbf u$$ are model control inputs to the system.

Correction

$$\begin{array}{|l|l|l|} \hline \text{Univariate} & \text{Univariate} & \text{Multivariate}\\ & \text{(Kalman form)} & \\ \hline & y = z - \bar x & \mathbf y = \mathbf z - \mathbf{H\bar x} \\ & K = \frac{\bar P}{\bar P+R}& \mathbf K = \mathbf{\bar{P}H}^\mathsf T (\mathbf{H\bar{P}H}^\mathsf T + \mathbf R)^{-1} \\ \mu=\frac{\bar\sigma^2\, \mu_z + \sigma_z^2 \, \bar\mu} {\bar\sigma^2 + \sigma_z^2} & x = \bar x + Ky & \mathbf x = \bar{\mathbf x} + \mathbf{Ky} \\ \sigma^2 = \frac{\sigma_1^2\sigma_2^2}{\sigma_1^2+\sigma_2^2} & P = (1-K)\bar P & \mathbf P = (\mathbf I - \mathbf{KH})\mathbf{\bar{P}} \\ \hline \end{array}$$

$$\mathbf H$$ is the measurement function.

$$\mathbf z,\, \mathbf R$$ are the measurement mean and noise covariance. They correspond to $$z$$ and $$\sigma_z^2$$ in the univariate filter. $$\mathbf y$$ and $$\mathbf K$$ are the residual and Kalman gain.

The details will be different than the univariate filter because these are vectors and matrices, but the concepts are exactly the same:

• Use a Gaussian to represent our estimate of the state and error
• Use a Gaussian to represent the measurement and its error
• Use a Gaussian to represent the process model
• Use the process model to predict the next state (the prior)
• Form an estimate part way between the measurement and the prior

### References:¶

1. Roger Labbe’s repo on Kalman Filters. (Majority of text in the notes are from this)
2. Probabilistic Robotics by Sebastian Thrun, Wolfram Burgard and Dieter Fox, MIT Press.